4(y^2+2y)-5(y^2-4)=

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Solution for 4(y^2+2y)-5(y^2-4)= equation:


Simplifying
4(y2 + 2y) + -5(y2 + -4) = 0

Reorder the terms:
4(2y + y2) + -5(y2 + -4) = 0
(2y * 4 + y2 * 4) + -5(y2 + -4) = 0
(8y + 4y2) + -5(y2 + -4) = 0

Reorder the terms:
8y + 4y2 + -5(-4 + y2) = 0
8y + 4y2 + (-4 * -5 + y2 * -5) = 0
8y + 4y2 + (20 + -5y2) = 0

Reorder the terms:
20 + 8y + 4y2 + -5y2 = 0

Combine like terms: 4y2 + -5y2 = -1y2
20 + 8y + -1y2 = 0

Solving
20 + 8y + -1y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(10 + -1y)(2 + y) = 0

Subproblem 1

Set the factor '(10 + -1y)' equal to zero and attempt to solve: Simplifying 10 + -1y = 0 Solving 10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1y = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1y = 0 + -10 -1y = 0 + -10 Combine like terms: 0 + -10 = -10 -1y = -10 Divide each side by '-1'. y = 10 Simplifying y = 10

Subproblem 2

Set the factor '(2 + y)' equal to zero and attempt to solve: Simplifying 2 + y = 0 Solving 2 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + y = 0 + -2 y = 0 + -2 Combine like terms: 0 + -2 = -2 y = -2 Simplifying y = -2

Solution

y = {10, -2}

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